0=12x^2-276x+1080

Solution for 0=12x^2-276x+1080 equation:

0=12x^2-276x+1080

We move all terms to the left:

0-(12x^2-276x+1080)=0

We add all the numbers together, and all the variables

-(12x^2-276x+1080)=0

We get rid of parentheses

-12x^2+276x-1080=0

a = -12; b = 276; c = -1080;
Δ = b2-4ac
Δ = 2762-4·(-12)·(-1080)
Δ = 24336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{24336}=156$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(276)-156}{2*-12}=\frac{-432}{-24}
=+18
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(276)+156}{2*-12}=\frac{-120}{-24}
=+5
$